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62 lines
1.9 KiB
62 lines
1.9 KiB
3 years ago
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## You pass butter
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### Return value
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We are now going to see how to declare a function that returns an argument.
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Let's say we declare the variable `ten` the following way.
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```js
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let ten = 5 + 5
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console.log(ten) // 10
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```
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We could replace those `5` with a very simple function that `returns` this
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result. Let's call this function `returnsFive`. Let's not put any arguments in
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this function to keep it very basic. The only new concept is the `return`
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keyword. This keyword will return the specified value **and** end the function
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execution.
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```js
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let returnsFive = () => {
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return 5
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// ↖ the keyword `return`, returns the value right after it,
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// in this case the number 5.
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}
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```
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Now that the function is declared, we call it where we need it.
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```js
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let ten = returnsFive() + returnsFive()
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console.log(ten) // 10
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```
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Now a question that you might ask yourself is: What if we had several `return`
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keywords in the same function? Well as mentioned before, the `return` also stops
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the function execution. So only the first `return` would matter. In fact that
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means that anything after the `return` would not be executed. Example:
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```js
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let returnsFive = () => {
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return 5 //ONLY this return is executed. Everything else is forgoten.
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return 10 // not executed (useless)
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return 'I am useless' // not executed either
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console.log('I am also useless') //nor this one
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}
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let ten = returnsFive() + returnsFive()
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console.log(ten) // 10
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//exactly the same result as the previous example
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```
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As you may see, we get exactly the same result as the previous example.
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`returnsFive` only returns 5. :)
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### Instructions
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As Rick's robot, you now know your purpose. (Remember? 'You pass butter.')
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Define the function `passButter` that returns `The butter`.
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